Question

7. x - 16x +48factor each trinomial

Answer 1

We have the following quadratic equation:

x - 16 x + 48

To factorize it, we need to find two integer numbers that:

A. Added together, the result will be equal to - 16

B. Mutiiplied together, the result will be equal to 48

Those numbers are - 12 and - 4:

A. - 12 + - 4 = -12 - 4 = - 16

B. -12 * -4 = - (-48) = 48

Now we can factorize, as follows:

Is x - 16 x + 48 or x2 - 16x + 48?

You don't answer, I will factorize both cases:

If the equation is x2 - 16x + 48, then the answer is:

(x - 12) (x -4) = 0 and the roots are:

`x_{1_(\square)}=16,x_{2\text{ = 4 }}`

If the equation is x - 16x + 48, then the answer is:

x - 16x + 48

-15x + 48

Dividing the coefficients by 3:

-5x + 16

-5x = -16

Dividing by -5:

-5x/-5 = -16/-5

x = 16/5

x = 3 1/5