Question

A compound contains 70% by mass of iron and 30% by mass of oxygen.

What is its empirical formula?
(A: 0, 16; Fe, 56]

Answer 1

Step-by-step explanation:

If we assume it's FexOy

Fe : O

70 : 30. (mass ratio)

x:y = 70/56 : 30/16. (mole ratio)

1.25 : 1.875

= 1.25/1.25: 1.875/1.25

= 1 : 1.5

=2 : 3

Therefore It's Fe2O3

Answer 2

FeO₂

Step-by-step explanation:

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