Question

Differentiate.F(x) = (6x + 1)²F'(x) =1600

Answer 1

we have the function

`f(x)=(6x+1)^2`

Find out the derivative

`\begin{gathered} f^(\prime)(x)=2(6x+1)^(2-1)(6x+1)^(\prime) \\ f^(\prime)(x)=2(6x+1)(6) \\ f^(\prime)(x)=12(6x+1) \\ f^(\prime)(x)=72x+12 \end{gathered}`

The answer is

f'(x)=72x+12