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Differentiate.F(x) = (6x + 1)²F'(x) =1600

User Kreys
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we have the function


f(x)=(6x+1)^2

Find out the derivative


\begin{gathered} f^(\prime)(x)=2(6x+1)^(2-1)(6x+1)^(\prime) \\ f^(\prime)(x)=2(6x+1)(6) \\ f^(\prime)(x)=12(6x+1) \\ f^(\prime)(x)=72x+12 \end{gathered}

The answer is

f'(x)=72x+12

User StarLord
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