Question

Suppose the population of a small town increases from 12,334 to 16,049. What is the percentincrease in the population, rounded to the nearest tenth of a percent?

Answer 1

First, we compute the population increase:

`16049-12334=3715.`

Now we divided the above result by the initial population:

`(3715)/(16049)\approx0.23147.`

Finally, we multiply by 100 and round to the nearest tenth of percent:

`100\cdot0.23147=23.147\approx23.1.`

Answer: 23.1%