Question

Using your understanding of the specific heat capacity, what mass of water in g (specific heat capacity =4.2J/g•°C) will increase from 30°C to 40°C if 250J are added to it?

Answer 1

Answer: 5.95 grams

Calculations:

We are given :

• mass of water = ?

• ΔT, =( Tfinal - T initial ) = ( 40 -30 )= 10 °C

,

• Q ,= 250J

,

• Specific heat capacity(,c,) = 4.2J/g•°C

We will the formula :

`Q\text{ = m}\cdot c\cdot\text{ }\Delta T\text{ }`

Therefore ;

`\text{Mass = Q/(c}\cdot\text{ }\Delta T)\text{ }`

Replacing the given parameters, we get that mass =

`\begin{gathered} \text{mass }=\frac{250J}{4.2J\cdot\text{ 10}\degree C}\cdot g\degree C \\ \text{ = 5.95 grams } \end{gathered}`

• This means that the mass required = 5.95 grams.