Question

1. An ordinary light bulb is marked “60A, 120V”, its resistance is ______.

Answer 1

In order to calculate the resistance, we can divide the voltage and the current, according to the formula below:

`R=(V)/(I)`

Where R is the resistance (in ohm), V is the voltage (in Volt) and I is the current (in Ampere).

So, using V = 120 V and I = 60 A, we have:

`R=(120)/(60)=2\text{ ohms}`

Therefore the resistance is 2 ohms.