Question

2Al + 3Cl₂ 2AlCl₃molar mass of AlCl3 => 133 g/molIf 25.0 moles of chlorine is used, how many grams of aluminum chloride can be produced?

Answer 1

Step-by-step explanation

Given:

2Al + 3Cl₂ 2AlCl₃

Molar mass of AlCl3 => 133 g/mol

Moles of Cl₂ = 25.0 mol

What to find:

The grams of aluminum chloride that can be produced.

Step-by-step solution:

Step 1: Determine the mole of AlCl₃ produced.

From the given chemical equation for the reaction,

3 mol Cl₂ produce 2 mol AlCl₃

So 25.0 mol Cl₂ will produce

`\frac{25.0mol\text{ }Cl_2*2mol\text{ }AlCl₃}{3mol\text{ }Cl_2}=16.67mol\text{ }AlCl₃`

16.67 moles of AlCl₃ produced.

Step 2: Calculated the grams of AlCl₃ produced.

Using the mole formula