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For y = 10*0.5^x (that is read y equals ten times one half to the power of x), doesthis model exponential growth or decay? Explain how you know.

User Ikechukwu
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f(x)=10\cdot((1)/(2))^x

f(1)=1/2 f(2)=(1/2)^2=(1/2)*(1/2)=1/4

1/2>1/4 => f(1)>f(2) => it is decreasing, because with the grow of x the value(y) is decreasing what we have shown

For y = 10*0.5^x (that is read y equals ten times one half to the power of x), doesthis-example-1
User Jonrobm
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