SOLUTION:
Step 1:
In this question, we are given the following:
Use the limit definition of the derivative to find the instantaneous rate of change of
Step 2:
The details of the solution are as follows:
An alternative way to find the use the limit definition of the derivative to find the instantaneous rate of change of:
![f(x)\text{ =}\sqrt[]{4x+8\text{ }}\text{ at x = 4}](https://img.qammunity.org/2023/formulas/mathematics/college/dtl9j2o27i78xmm4bkpnaz177knlxtgx4j.png)
Let us take the derivative of the function and we have that:
![\begin{gathered} f(x)\text{ = }\sqrt[]{4x+8}=(4x+8)^{(1)/(2)} \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/td71iarn0sspiw8bmbhv6d9m3vh3dep31s.png)

![\begin{gathered} f^I(4)=2(16+8)^{-(1)/(2)} \\ f^I(4)\text{ = 2 x }\frac{1}{\sqrt[]{24}} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/kjkigcisldmsaa5tibkrz7zancjv6yes4r.png)
![f^I(4)\text{ =}\frac{2}{\sqrt[]{24}}](https://img.qammunity.org/2023/formulas/mathematics/college/ncrx9q0avzal8m6y7hi03j68jppn32895l.png)
![f^I(4)=\frac{2}{\sqrt[]{24}}=\frac{2}{\sqrt[]{4}X\sqrt[]{6}}=\frac{2}{2X\sqrt[]{6}}=\frac{1}{\sqrt[]{6}}](https://img.qammunity.org/2023/formulas/mathematics/college/l3daxkj6qhmotd2vgmdgifyiigrz71z23w.png)
![f^I(4)\text{ =}\frac{1}{\sqrt[]{6}}](https://img.qammunity.org/2023/formulas/mathematics/college/92nmryg5cocjezcod08zy2lgcoug7hmnza.png)