Question

Find the 11th term of the sequence: 32805, 10935, 3645...

Answer 1

first term a=32805

common ration: r=10935/32805=1/3

11th term:

`\begin{gathered} a_(11)=32805((1)/(3))^(11-1) \\ a_(11)=32805((1)/(3))^(10) \\ a_(11)=32805((1)/(59049)) \\ a_(11)=0.555 \end{gathered}`

So the 11th term is 0.555