Question

`(5)/(3)s = (15)/(3) + (3)/(2)s - (1)/(4)`i dont under stand it and other questions like it because I'm sorta slower than the rest of my class. We're doing Types of Solutions of Linear Equations.

Answer 1

The question we have to solve is:

`(5)/(3)s=(15)/(3)+(3)/(2)s-(1)/(4)`

To solve this equation, we take all the "s"'s to one side and numbers to the other and simplify:

`\begin{gathered} (5)/(3)s=(15)/(3)+(3)/(2)s-(1)/(4) \\ (5)/(3)s-(3)/(2)s=(15)/(3)-(1)/(4) \\ (5(2)-3(3))/(6)s=(15(4)-1(3))/(12) \\ (1)/(6)s=(57)/(12) \\ s=((57)/(12))/((1)/(6)) \end{gathered}`

When we want to divide by a fraction, we mulitply by its reciprocal. So,

`\begin{gathered} s=((57)/(12))/((1)/(6)) \\ s=(57)/(12)*(6)/(1) \\ s=(57)/(2) \end{gathered}`