68.1k views
2 votes
It is given that the equation (mx)²+ 5nx+4=0 has two equal real roots while the quadratic equation px²-x+m=0 has two distinct roots where m,n and p are constants. Express the range of n in terms of p

User MusicMan
by
5.2k points

1 Answer

5 votes

Given:


(mx)^2+5nx+4=0\text{ has two equal real roots}
px^2-x+m=0\text{ has distict roots. }

Taking the first equation:


a=m^2\text{ ; b=5n ; c=4 }
b^2-4ac=0
25n^2-4m^2(4)=0
(5n)^2-(4m)^2=0
(5n+4m)(5n-4m)=0
5n+4m=0\text{ ; 5n-4m=0}
m=-(5)/(4)n\text{ ; m=}(5)/(4)n
4m=-5n\text{ ; 4m=5n}

Taking the second equation:


a=p\text{ ; b=-1 ; c=m}
b^2-4ac>0
1-4pm>0

If 4m=5n,


1-p(5n)>0
1>p(5n)
(1)/(5p)>n

If 4m=-5n,


1-p(-5n)>0
1+5pn>0
5pn>-1
n>-(1)/(5p)

Range of n in terms of p:


(1)/(5p)>n>-(1)/(5p)[tex]-\frac{1}{5p}
User Revmatcher
by
4.6k points