Step-by-step explanation:
The maximum no. of electrons in a shell is given by. 2n^2 .
So for
n= 5 , 2× 5× 5 = 50
n=2 , 2×2×2 = 8
For a sub shell the maximum no. of electrons possible is given by 2(2l + 1)
So for n= l= 0
2 [(2×0) +1] = 2
for n=2 l=1
2 [(2×1) + 1] = 6
3d
d sub shell has l= 2 quantum number
Therefore 2[ (2×2) + 1] = 10
2s
s sub shell has l=0 quantum number
2 [(2×0) +1] = 2
5f
f sub energy level has l=3 quantum number
So 2[ (2×3) +1 ] = 14
The azimuthal quantum numbers for the sub shells are as follows
( s ---> 0
p----> 1
d----> 2
f ----> 3 )