We have the points J(3,3.5) and K(6,5)
The line passing through these points is expressed by an equation in the form y = a*x + b
It's slope (a) is given by (yk - yj)/(xk - xj) = (5 - 3.5)/(6 - 3) = 1.5/3 = 0.5 = a
We get b replacing y and x from the equation by K coordinates (could also be J coordinates).
For y = 5 and x = 6, we have:
5 = 0.5*6 + b, which implies 5 = 3 + b
Subtracting both sides from this equation by 3, we got: b = -2
Therefore, the equation of the line is y = 0.5*x + 2