Question

There are three boxes, each of which contains balls with numbers from 0 to 9. One ball is taken out of each box. What is the probability thata) three units are drawn;b) three equal numbers are drawn?

Answer 1

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the formula for probability

`probability=\frac{number\text{ of required outcomes}}{number\text{ of total possible outcomes}}`

STEP 2: Write the number of outcomes

There are 0-9 numbers which are 0,1,2,3,4,5,6,7,8,9 which makes it 10 total possible outcomes.

STEP 3: Find the probability that three units are drawn

`Pr(3\text{ units\rparen}=Pr(1\text{ unit\rparen}* Pr(2nd\text{ unit\rparen}* Pr(3rd\text{ unit\rparen}`

Find the probability that a unit is drawn:

`Pr(1\text{ unit\rparen}=(1)/(10)`

The probability that three units are drawn will be: