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Two football players, one with a mass of 89.3 kg and the other with a mass of 94.8 kg, are running at a velocity of 8.32 m/s. If they are both headed in the same direction, what is the total momentum?

User EliSquared
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1 Answer

3 votes

The momentum of first player can be given as,


p_1=m_1v

The momentum of second player can be given as,


p_2=m_2v

The total momentum of both the players can be given as,


p=p_1+p_2

Plug in the known expressions,


\begin{gathered} p=m_1v+m_2v \\ =(m_1+m_2)v \end{gathered}

Substitute the known values,


\begin{gathered} p=(89.3\text{ kg+94.8 kg)(8.32 m/s)} \\ =(184.1\text{ kg)(8.32 m/s)}(\frac{1\text{ N}}{1kgm/s^2}) \\ =1531.7\text{ Ns} \end{gathered}

Thus, the total momentum of both the players is 1531.7 Ns.

User Vivere
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