Given:
The electric field intensity between the parallel plates is,

The distance between the plates is doubled and the charges are halved.
The area of the plates is tripled.
To find:
the new electric field
Step-by-step explanation:
The electric field intensity between the parallel plates is,

Q is the charge on each plate and A is the area of each plate.
Now the field intensity is,

Hence, the new electric field intensity is d.
