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A rectangular door has an area of X^2+3x-28. If the width of the door is (X-4), what is the length?

A rectangular door has an area of X^2+3x-28. If the width of the door is (X-4), what-example-1
User Terion
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1 Answer

3 votes

Since the door is rectangular, its area is the multiplication of its width by its length:


A=w\cdot l

We know its area and width:


x^2+3x-28=(x-4)\cdot l

Since the area is a polynomial of second degree and the width is a polynomial of first degree, so it is expected that the length is also a first degree polynomial to complete the equation like this:


x^2+3x-28=(x-4)\cdot(x+b)

But, to make this, we can use polynomial synthetic division.

We will do the division:


(x^2+3x-28)/(x-4)=l

To do this, we look first to the denominator. Since it is x - 4, we pick the coefficient, change its sign and put it first:

4 |

|

|

Now, we take the coefficients of the numerator in order (from greater degree to lower) and put them. The coefficients are 1, 3 and -28, so:

4 | 1 3 -28

|

| 1

We also copy the first to the last row. Now, we will multiply the one in the last row by the "4" and put it under the next coefficient. 1 times 4 is 4, so:

4 | 1 3 -28

| 4

| 1

And now we add them and put the result in the last row:

4 | 1 3 -28

| 4

| 1 7

And now, we repeat:

4 | 1 3 -28

| 4 28

| 1 7

4 | 1 3 -28

| 4 28

| 1 7 0

The result is in the last row. the last is the remainder (which is 0, so there are no remainder), and the rest is the polynomial, the quotient:


\begin{gathered} 1\, \, \, \, \, \, \, \, 7 \\ x+7 \end{gathered}

So, this means that:


l=(x^2+3x-28)/(x-4)=x+7

Thus, the length is x + 7.

User Woooody Amadeus
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