Question

To find the moles of the amount of lead nitrate used. Would I use milliliters or liters to calculate it? Pb(NO3)2 is 0.25 M and the liter of Pb^2+ is 0.35 mL

Answer 1

Moles Pb²⁺ = 8.75 x 10⁻⁵ mol

Step-by-step explanation

The unit of concentration (that is molarity) is mol/L, therefore, the unit of volume must be in liters to get the moles of Pb^2+

Given that:

Molarity of Pb(NO₃)₂ = 0.25 M

Volume of Pb²⁺ = 0.35 mL = (0.35/1000) = 3.5 x 10⁻⁴ L

What to find:

The moles of Pb²⁺.

Solution:

Moles Pb²⁺ = [Pb(NO₃)₂] x V Pb²⁺

Moles Pb²⁺ = 0.25 M x 3.5 x 10⁻⁴ L

Moles Pb²⁺ = 8.75 x 10⁻⁵ mol