we have the coordinates of triangle ABC
A(2,4) B(-2,8) C(0,10)
step 1
Reflection over the line x=-2
Remember that
the line x=-2 ----> is a vertical line
so
the y-coordinates of the image are the same y-coordinates of the pre-image
A(2,4) -----------> A'(-6,4)
the x-coordinate of the image is -6
because, the distance of the point A to the line x=-2 is equal to 4 units, so the distance of the line x=-2 to the image must be equal to 4 units too.
B(-2,8) ----------> B'(-2,8)
is the same point, because is located on the reflection line
C(0,10) --------> C'(-4,10)
step 2
Dilation with a scale factor of 0.5
the rule is
(x,y) -----> (0.5x,0.5y)
so
A'(-6,4) -----> A''(-3,2)
B'(-2,8) ----> B''(-1,4)
C'(-4,10) ----> C''(-2,5)
using a graphing tool
one minute to draw the figure