Question

A ball is thrown vertically upwards at 25 m/s. Gravity causes the ball to

decelerate at 10 m/s². Calculate the maximum height the ball will reach.

Answer 1

31.25m

Step-by-step explanation:

using the formula

`v {}^(2) = u {}^(2) + 2as`

where v = final velocity = 0

u = initial velocity = 25

a = acceleration = -10 as its thrown upwards

s = distance (max height) = ?

rearranging the equation to find s:

`s = \frac{ {v}^(2) - {u}^(2) }{2a}`

`s = \frac{0 {}^(2) - (25) {}^(2) }{2( - 10)} = 31.2m`