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Write an equation in STANDARD FORM that has x-intercepts at x=-2 and x=5

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SOLUTION

A quadratic equation in standard from will be in the form


ax^2\text{ + bx + c = 0}

From x = -2 and x = 5, we have


\begin{gathered} x\text{ = -2 and }x\text{ = }5 \\ x\text{ + 2 = 0 and }x\text{ - 5 = 0 multiplying we have } \\ (x\text{ + 2) }(x\text{ -5) } \\ x^2\text{ -5x +2x -10 = 0} \\ x^2\text{ -3x - 10 = 0} \end{gathered}

User Nick Eagle
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