Awnser the question below factor the following polynomial into linear factors real and complex and find all zeros p(x)=x^3+2x^2+9x+18

Question

asked Mar 23, 2023 11.2k views

1 Answer

Pierre Valade · Answer 1 · 2023-03-26T15:10:43+0000

we have the polynomial

$p\mleft(x\mright)=x^3+2x^2+9x+18$

For x=-2

the value of p(x) is equal to zero

so

(x+2) is a linear factor

Find out the other factors

Divide

x^3+2x^2+9x+18 : (x+2)

x^2+9

-x^3-2x^2

-------------------------

9x+18

-9x-18

-------------

0

so

x^3+2x^2+9x+18=(x+2)(x^2+9)

Solve the quadratic equation