Question

A jet is traveling at 458 m/s when a parcel is dropped from the jet. If the jet is 8000 m high how far forward horizontally from the spot where it leaves the jet does the parcel move during its drop? Please input your answer as a positive value with two decimal places.

Answer 1

The time taken by parcel to cover the vertical distance is,

`t=\sqrt[]{(2h)/(g)}`

Plug in the known values,

`\begin{gathered} t=\sqrt[]{\frac{2(8000\text{ m)}}{9.8m/s^2}} \\ \approx40.4\text{ s} \end{gathered}`

The horizontal distance covered by parcel is,

`d=ut`

Substitute known values,

`\begin{gathered} d=(458\text{ m/s)(40.4 s)} \\ =18503.2\text{ m} \end{gathered}`

Thus, the horizontal distance covered by parcel is 18503.2 m.