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If f(x)=(-x)^3-x^2-x+15What would f(-5) = to?

User Jeiwan
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1 Answer

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Given the equation:


f(x)=(-x)^3-x^2-x+15

To find f(-5), substitute x by -5 and solve the equation.


f(-5)=[-(-5)\rbrack^3-(-5)^2-(-5)+15

To solve it, first, solve the signs and the exponents.


\begin{gathered} f(-5)=5^3-(-5)^2+5+15 \\ f(-5)=125-25+20 \\ f(-5)=120 \end{gathered}

Answer: f(-5) = 120.

User Abhishek Verma
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