210k views
5 votes
A 12.4 m long wire sits in a magnetic field. The force it feels is 21 N as 9.4 A of current flow through it. How strong is the magnetic field it sits in to 2 decimal places?

User TerryTsao
by
3.1k points

1 Answer

4 votes

ANSWER

B = 0.18T

Step-by-step explanation

Given:

• The length of the wire, L = 12.4m

,

• The current flowing through the wire, I = 9.4A

,

• The force experimented by the wire, F = 21N

Unknown:

• The strength of the magnetic field, B

The equation for the force on a wire of length L in a perpendicular magnetic field of strength B while a current I is flowing through it is,


F=B\cdot I\cdot L

Solving for B,


B=(F)/(I\cdot L)=(21N)/(9.4A\cdot12.4m)\approx0.18T

Hence, the strength of the magnetic field is 0.18 Tesla.

User Andrew Mackrodt
by
3.3k points