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find the the equations of the circle passing through (1, 4) and having the diameters of 3x-4y=1 and 2x+y=8?

User Kevin Kibler
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1 Answer

14 votes
14 votes

Answer:

In order to write the equation of a circle, we need two things their centre as well as the radius. so….diameter always intersect each other at the centre of the circle, hence after solving the equation of diameter, we get the intersecting point(x, y)=(3,2). now, we have already given one point…and as per the question circle passing through that point itself. so by applying distance formula, we can obtain the value of radius. thus we get radius 2√2. now we have required things to get the equation of a circle. we know the standard equation of circle having centre =(x1,y1) and radius = r is (x-x1)²+(y-y1)²=r² hence we can find the equation of circle by putting the coordinate (x1,y1)=(3,2) and radius =2√2 in the above mentioned standard equation.

Explanation:

:3

User Steve Hatcher
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