231k views
1 vote
. What pressure will be exerted by 0.7 mol of a gas at 23 C when contained in a vessel whose volume is 1.1 L?

User Damarys
by
7.1k points

1 Answer

4 votes

Answer:

15.46atm

Explanations:

According to the ideal gas equation;


PV=nRT

where:

• P is the ,pressure ,of the gas

,

• V is the volume of the gas = 1.1L

,

• n is the number of moles = 0.7mol

,

• R is the ,Gas constant, = 0.08206Latm/molK

,

• T is the temperature = 23 + 273 = 296K

Substitute the given parameters into the formula


\begin{gathered} P=(nRT)/(V) \\ P=(0.7*0.08206*296)/(1.1) \\ P=(17.0028)/(1.1) \\ P=15.46atm \end{gathered}

Hence the pressure of the gas that will be exerted is 15.46atm

User Jimmygchen
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.