SOLUTION
We are told to use the discriminant to determine whether the quadratic equation has two unequal real solutions, a repeated real solution, or no real solution, without solving the equation
![9x^2-7x+8=0](https://img.qammunity.org/2023/formulas/mathematics/college/70e1m0v0r0uinqn2wsqeinv4kz9it4vnlx.png)
The discriminant formula is given by
![d=b^2-4ac](https://img.qammunity.org/2023/formulas/mathematics/college/okv9ev7nqgse2ybwvnmabsz5ci97w66k91.png)
Where d is the discriminant.
If
![\begin{gathered} d>0,\text{ we have 2 real roots} \\ \\ d=0,we\text{ have 1 real root} \\ \\ d<0,we\text{ have 2 complex roots } \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/tb3hmbxwi8n7khwpn58i5cs4thg3iptttl.png)
Now
![\begin{gathered} b^2-4ac \\ \\ -7^2-4*9*8 \\ \\ 49-288 \\ \\ =-239 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/6q70fed47dnwf2ntxs977elb5lj1dw7vrg.png)
So, since our value for d < 0, the equation has 2 complex roots.
Therefore, the equation has no real solution
So, the last option is the correct answer.