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5(2r + 1) - 3 (- 4r + 2)
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5(2r + 1) - 3 (- 4r + 2)

User Mattsilver
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1 Answer

5 votes

We have to rearrange the expression:


\begin{gathered} 5(2r+1)-3(-4r+2) \\ 5\cdot2r+5\cdot1-3\cdot(-4r)-3\cdot2 \\ 10r+5+12r-6 \\ (10+12)\cdot r+5-6 \\ 22r-1 \end{gathered}

Answer: 22r-1

User Jeremy Mullin
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