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Passing through ( - 6,- 2) and parallel to the line whose equation is y = - 5x + 5.Write and equation for the line in point slope form and in slope intercept form

User AxelWass
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SOLUTION;

Sine it is parallel to the line whose equation is y = - 5x + 5, it means the slope of the new line is also - 5.


\begin{gathered} \text{Point = (-6. -2)} \\ \text{Slope = -5} \end{gathered}
y-y_1=m(x-x_1)
\begin{gathered} y-(-2)\text{ = -5(x-(-6))} \\ y\text{ + 2 = -5 ( x + 6)} \end{gathered}

User Seaotternerd
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