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How much heat must be absorbed by 125 gg of ethanol to change its temperature from 22.3 ∘C∘C to 31.0 ∘C∘C? (Specific heat capacity of ethanol is 2.42 J/g∘CJ/g∘C)

How much heat must be absorbed by 125 gg of ethanol to change its temperature from-example-1

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The specific heat capacity of a substance is the amount of energy required to raise the temperature of 1 kg of the substance by 1 degree celsius. The formula for calculating the heat is expressed as

H = mcθ

where

θ is the change in temperature(final temperature - initial temperature)

m is the mass of the substance in kg

c is the specific heat capacity

From the information given,

initial temperature = 22.3

final temperature = 31

θ = 31 - 22.3 = 8.7

m = 125g

We would convert 125g to kg

recall, 1 kg = 1000g

125g = 125/1000 = 0.125kg

c = 2.42

H = 0.125 x 2.42 x 8.7

H = 2.63J

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