Let be "r" the amount of money (in dollars) they are charging for a regular gift basket and "d" the amount of money (in dollars) they are charging for a deluxe gift basket.
Based on the information given in the exercise, you can set up the following System of equations:

You can solve the System of equations using the Substitution method:
1. Solve for "r" from the second equation:

2. Substitute the new equation into the first original equation.
3. Solve for "d" in order to find its value.
Then:

4. Knowing the value of "d", you can substitute it into the following equation, and then you must evaluate in order to find the value of "r":

Then, this is:

The answer is: They are charging $25 for a regular gift basket and $43 for a deluxe gift basket.