Question

If 1.85 grams of Mg(OH)2 reacts with 3.71 grams of HCl how much MgCl2 is produced?what is the limiting reactant? 1Mg(OH)2+2HCl=1MgCl2+2H2O

Answer 1

Mg(OH)2 is the limiting reactant

Mass of MgCl2 produced = 3.02 g

Step-by-step explanation

Given: The balanced chemical equation

mass of Mg(OH)2 = 1.85 g

mass of HCl = 3.71

Solution

Mg(OH)2

`1.85g\text{ Mg\lparen OH\rparen}_2\text{ x }\frac{1\text{ mol Mg\lparen OH\rparen}_2}{58,3197g}\text{ x }\frac{1\text{ MgCl}_2}{1\text{ Mg\lparen OH\rparen}_2}\text{ = 0.031 mol MgCl}_2`

HCl

`3.71g\text{ HCl x }\frac{1\text{ mol HCl}}{36,458g}\text{ x }\frac{1\text{ MgCl}_2}{2\text{ HCl}}\text{ = 0.051 mol MgCl}_2`

Therefore Mg(OH)2 is the limiting reactant.

Calculation of MgCl2 mass

`0.031\text{ mol MgCl}_2\text{ x }\frac{95,211g}{1\text{ mol MgCl}_2}\text{ = 3.02 g}`