In order to answer this question we will need the properly balanced reaction, which the question already gave us:
C5H12 + 8 O2 -> 5 CO2 + 6 H2O
Then we need to focus on the compounds that the question is asking, which are C5H12 and 5 CO2, from the reaction we can also identify the molar ratio between both molecules, 1:5, that means that for every mole of C5H12, we will end up with 5 moles of CO2
Now let's find out how many moles of C5H12 are in 25.5 grams of it, we will use its molar mass to find the answer, molar mass is 72.15 g/mol
72.15 g = 1 mol
25.5 g = x moles
x = 0.35 moles of C5H12
Now we have 0.35 moles of C5H12, we know that molar ratio is 1:5, now let's see how many moles of CO2 we will have
1 C5H12 = 5 CO2
0.35 C5H12 = x CO2
x = 1.75 moles of CO2
And now we will do a similar step using CO2 molar mass in order to find the final mass, molar mass for CO2 is 44.01 g/mol
44.01 g = 1 mol
x grams = 1.75 moles
x = 77.02 grams of CO2