Question

What is the equation of the line that passes through the point (8,-8) and has a slope of -2​

Answer 1

• Point=(8,-8)
• m=-2

.Equation of line in point slope form

`\\ \sf\longmapsto y-y_1=m(x-x_1)`

`\\ \sf\longmapsto y+8=-2(x-8)`

`\\ \sf\longmapsto y+8=-2x+16`

`\\ \sf\longmapsto 2x+y+8-16=0`

`\\ \sf\longmapsto 2x+y-8=0`

Answer 2

y=-2x+8

Explanation:

Hi there!

We want to find the equation of the line that passes through the point (8, -8) and has a slope of -2

We can write this equation in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept

Since we already know the slope of the line, we can immediately plug it into the equation as m:

y=-2x+b

Now we need to find b

As the equation of the line passes through the point (8, -8), we can use it to help solve for b, since (8, -8) is a solution to the equation, meaning that it will yield a true statement when plugged into the equation

So substitute 8 as x and -8 as y:

-8=-2(8)+b

Multiply

-8=-16+b

Add 16 to both sides

8=b

Now substitute 8 as b into the equation:

y=-2x+8

Hope this helps!