Question

7/21/22, 7:37 AMProblem Set ThreeNotes: Use 9.8 m/s 2 for the acceleration due to gravity. Formust be expressed in m/sLaw calculations, mass must be expressed in kg and velocity.A man with a mass of 110kg slides down a vertical pole with an acceleration of 9 m/s2. What is the frictional force acting on the man?

Answer 1

Given:

The mass of the man is m = 110 kg

The man slides down with acceleration,

`a=9\text{ m/s}^2`

The acceleration due to gravity is

`g=\text{ 9.8 m/s}^2`

Required: The frictional force acting on the man.

Step-by-step explanation:

The equation of motion to calculate frictional force is given as

`\begin{gathered} mg-f=ma \\ f=mg-ma \\ =m(g-a) \end{gathered}`

On substituting the values, the frictional force will be

`\begin{gathered} f=110(9.8-9) \\ =\text{ 88 N} \end{gathered}`

Final Answer: The frictional force is 88 N