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You need a 55% alcohol solution. On hand, you have a 150mL of a 45% alcohol mixture. You also have 80% alcohol mixture. How much of the 80% mixture will you need to add to obtain the desired solution?

User Spekdrum
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1 Answer

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Let the equired amount of 80% alcohol mixture required be 'x' mL.

If C represents the concentration and V represents the correspon

User Pachanga
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