Question

I can’t figure this out!! My answer is way different then the book!

Answer 1

Given:

`(1)/(3)p^3\text{ + }(3)/(4)p^2\text{ - p -\lbrack}(1)/(2)p^3\text{ + }(1)/(3)p^2\text{ + }(1)/(2)p]`

Simplifying:

`\begin{gathered} =\text{ }(1)/(3)p^3\text{ + }(3)/(4)p^2\text{ - p -}(1)/(2)p^3\text{ - }(1)/(3)p^2\text{ - }(1)/(2)p \\ Collect\text{ like terms} \\ =\text{ }(1)/(3)p^3\text{ - }(1)/(2)p^3\text{ + }(3)/(4)p^2\text{ - }(1)/(3)p^2\text{ - p - }(1)/(2)p \end{gathered}`

Simplifying further:

`\begin{gathered} =\text{ }(2-3)/(6)p^3\text{ +}(9-4)/(12)\text{ p}^2\text{ +}(-2-1)/(2)p \\ =-(1)/(6)p^3\text{ + }(5)/(12)p^2\text{ - }(3)/(2)p \end{gathered}`

Answer:

`=-(1)/(6)p^3\text{ + }(5)/(12)p^2\text{ - }(3)/(2)p`