Question

What is the X-intercept of c = - 6t^2 + 90t - 156

Answer 1

Given;

`c=-6t^2+90t-156`

The x-intercepts are the points where y=0.

Thus;

`\begin{gathered} -6t^2+90t-156=0 \\ \\ -t^2+15t-26=0 \\ \\ -t^2+2t+13t-26=0 \\ \\ -t(t-2)+13(t-2)=0 \\ \\ t=2,t=13 \\ \end{gathered}`

Hence, the x-intercepts are;

`(2,0)\text{ and }(13,0)`