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Solve for x:x/6 + 3 ≥ −2

User NickJ
by
4.3k points

1 Answer

1 vote

x\ge-30

Step-by-step explanation


(x)/(6)+3\ge-2

Step 1

subtract 3 in both sides.


\begin{gathered} (x)/(6)+3\ge-2 \\ (x)/(6)+3-3\ge-2-3 \\ (x)/(6)\ge-5 \end{gathered}

Step 2

Multiply both sides by 6


\begin{gathered} (x)/(6)\ge-5 \\ (x)/(6)\cdot6\ge-5\cdot6 \\ x\cdot(6)/(6)\ge-30 \\ x\cdot1\ge-30 \\ x\ge-30 \end{gathered}

so, the answer is


x\ge-30

I hope this helps you

User Sgwill
by
5.7k points