The expression for the volume of cone is :

Since from the given figure we have, height of cone h= 12 mm
and from the given data, volum is V = 1519.76 cubic milimeter.
Subtitute the values in the expression for the volume of cone and solve for radius r,
![\begin{gathered} V=(1)/(3)\Pi r^2h \\ 1519.76=(1)/(3)\Pi r^2(12) \\ \text{ since, }\Pi=3.14 \\ (1519.76*3)/(\Pi(12))=r^2 \\ r^2=(4559.28)/(37.68) \\ r^2=121 \\ r=\sqrt[]{121} \\ r=11\text{ mm} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/do3a187gn8bo43ajdwtooxr3o9t0vkj4l9.png)
So, the radius of cone is 11 mm.
Answer : 11 mm