Question

Could someone help solve question 50? (One on left) thanks!!

Answer 1

First we are going to use the sin trigonometric function to find x,

`\sin 45\text{ = }\frac{12\text{ cm}}{x}\Rightarrow\text{ x= }\frac{12\text{ cm}}{\sin 45}=\text{ }\frac{12\text{ cm}}{\frac{\sqrt[]{2}}{2}}=\frac{24}{\sqrt[]{2}}cm=\text{ 12}\sqrt[]{2}\text{ cm}`

Now, we do the analogous procedure for the angle of 30 degrees

`\begin{gathered} \sin 30=\text{ }(x)/(z)\text{ }\Rightarrow\text{ z=}\frac{x\text{ }}{\sin 30}=\frac{12\sqrt[]{2}\text{ cm}}{(1)/(2)}=\text{ 24}\sqrt[]{2\text{ }}cm \\ \tan 30=\text{ }(x)/(y)\text{ }\Rightarrow\text{ y= }\frac{x}{\text{tan}30}=\frac{12\sqrt[]{2}cm}{\frac{\sqrt[]{3}}{3}}=\text{ 12}\sqrt[]{2}\sqrt[]{3}\text{ cm =12}\sqrt[]{6}\text{ cm} \end{gathered}`