Question

Solve the system using graphing, substitution or elimination. If needed, round solutions to the nearest tenth.

Answer 1

The given equation:

`\begin{gathered} -3y^2+44x-2y-191=0 \\ x-y-1=0 \end{gathered}`

From the second equation

`x=1+y`

Substitute x=1+y into the first equation

`\begin{gathered} -3y^2+44(1+y)-2y-191=0 \\ -3y^2+44+44y-2y-191=0 \\ -3y^2+42y=147 \\ \Rightarrow y=7 \end{gathered}`

Substitute y=7 into the equation x=1+y, it follows:

This gives

`x=1+7=8`

Therefore the solutions are

`x=8,y=7`