Answer:
D. x > -3 and x < 1
Explanation:
There is an absolute value in this inequality, so we have to solve for 2 instances -- where the quantity in the absolute value is positive, and where it is negative.
First, we will isolate the absolute value by dividing by 3:
3|x + 1| < 6
|x + 1| < 2
Then, because this is a less-than case of the absolute value, we can put it in between the positive and negative absolute values of the other side:
-|2| < x + 1 < |2|
-2 < x + 1 < 2
and solve.
-3 < x < 1
(this can also be written as x > -3 and x < 1)