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Graph the line that passes through the points (−6,3) and (−5,3) and determine the equation of the line.

1 Answer

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Given that the line passes through the points (-6,3) and (-5,3),

First we will find slope between given points,


\begin{gathered} m=(y_2-y_1)/(x_2-x_1) \\ m=(3-3)/(-5+6) \\ m=(0)/(3) \\ m=0 \end{gathered}

Now, we will use two points form to find equation of line


\begin{gathered} y-y_1=m(x_{}-x_1) \\ y-5=0(x-6) \\ y-5=0 \\ y=5 \end{gathered}

Hence , y=5 is the required answered.