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There are 6 woman running in a race. How many first second and third place possibilities can occur?

User Wackozacko
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1 Answer

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Permutation formula:


P(n,r)=(n!)/((n-r)!)

In this case:

n is the nuber of woman in the race

r is the number of woman chosen (3 as you need to know the number of possibles 3 first places combinations)


\begin{gathered} P(6,3)=(6!)/((6-3)!) \\ \\ =(6!)/(3!) \\ \\ =(1\cdot2\cdot3\cdot4\cdot5\cdot6)/(1\cdot2\cdot3) \\ \\ =4\cdot5\cdot6 \\ \\ =120 \end{gathered}

Then, there are 120 first second and third place possibilities that can occur

User Lior Hirschfeld
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