A 1.5 kg cart is attached to a spring with spring constant of 5 N/m. The cart & spring is pulled to stretch the spring by 3 meters. What is the SPE?

Jan Gressmann asked Sep 28, 2022

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3 votes

A 1.5 kg cart is attached to a spring with spring constant of 5 N/m. The cart & spring is pulled to stretch the spring by 3 meters.

What is the SPE?

Jan Gressmann asked Sep 28, 2022

2.6k points

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11 votes

22.5 J

Step-by-step explanation:

Given:

x = 3 m

$k = 5\:\text{N/m}$

The spring potential energy
PE_s is

$PE_s = (1)/(2)kx^2 = (1)/(2)(5\:\text{N/m})(3\:\text{m})^2$

$\:\:\:\:\:\:\:=22.5\:\text{J}$

Robert Bean answered Oct 2, 2022

3.2k points

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