Small drink: 12 ounces
Large Drink: 36 ounces
Step-by-step explanation
Step 1
set the equations
let x represents the number of ounces of one small drink
let y represents the number of ounces of a large drink
hence
a)three small drinks and two large drinks contain 108 ounces of cola
![3x+2y=108\rightarrow equation(1)](https://img.qammunity.org/2023/formulas/mathematics/college/fm90gy6ckk29ffsd153wi57od6shvf9f4o.png)
b)A small drink contains a third as much cola as a large drink
![x=(1)/(3)y\rightarrow equation(2)](https://img.qammunity.org/2023/formulas/mathematics/college/70qf3rjmtwghew8pfsc4u13m9wrymrpnkq.png)
Step 2
solve the equations
![\begin{gathered} 3x+2y=108\rightarrow equation(1) \\ x=(1)/(3)y\rightarrow equation(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/8kuxujbtjveonlq0xdchdbxwikvas1wkgl.png)
a) replace the x value from equation (2) into equation (1) and solve for y
![\begin{gathered} 3x+2y=108\rightarrow equation(1) \\ 3((1)/(3)y)+2y=108\rightarrow equation(1) \\ y+2y=108 \\ 3y=108 \\ \text{divide both sides by 3} \\ (3y)/(3)=(108)/(\cdot3) \\ y=36 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/w3v42ogd7dhec8aqvs4y215bv1m1y9cbnr.png)
b) now, replace the y value into equaiton (2) to find the x value
![\begin{gathered} x=(1)/(3)y\rightarrow equation(2) \\ x=(1)/(3)36 \\ x=12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bh0d2uhrmjuavjf40mcyoetv0slyf3b838.png)
therefore:
Small drink: 12 ounces
Large Drink: 36 ounces
I hope this helps you