The graph of the original function is:
The question asks us to find the value of the new graph.
In the orignal graph, when x = 0, y = 1 i.e:

This is the value for the original graph.
In the question we are asked, the value of y when x = 0 is not 1. This means that the graph has been shifted to the right.
Whenever a graph has been shifted to the right by n units, you must subtract n from the x-term of the function.
Let us put this into mathematics:

In order to find the value of n, we need to study the new graph and substitute a coordinate point from it into the new equation above.
From studying the new graph, when x = 1, y = 1 as well. Hence, we can find n using this coordinate

Therefore, the new graph is:
